8x(x+4)=7(x-7)+6

Solution for 8x(x+4)=7(x-7)+6 equation:

8x(x+4)=7(x-7)+6

We move all terms to the left:

8x(x+4)-(7(x-7)+6)=0

We multiply parentheses

8x^2+32x-(7(x-7)+6)=0


We calculate terms in parentheses: -(7(x-7)+6), so:

7(x-7)+6

We multiply parentheses

7x-49+6

We add all the numbers together, and all the variables

7x-43

Back to the equation:

-(7x-43)


We get rid of parentheses

8x^2+32x-7x+43=0

We add all the numbers together, and all the variables

8x^2+25x+43=0

a = 8; b = 25; c = +43;
Δ = b2-4ac
Δ = 252-4·8·43
Δ = -751
Delta is less than zero, so there is no solution for the equation