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8x(x-5)=72
We move all terms to the left:
8x(x-5)-(72)=0
We multiply parentheses
8x^2-40x-72=0
a = 8; b = -40; c = -72;
Δ = b2-4ac
Δ = -402-4·8·(-72)
Δ = 3904
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{3904}=\sqrt{64*61}=\sqrt{64}*\sqrt{61}=8\sqrt{61}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-40)-8\sqrt{61}}{2*8}=\frac{40-8\sqrt{61}}{16} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-40)+8\sqrt{61}}{2*8}=\frac{40+8\sqrt{61}}{16} $
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