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8x(x-6)=5(x-6)
We move all terms to the left:
8x(x-6)-(5(x-6))=0
We multiply parentheses
8x^2-48x-(5(x-6))=0
We calculate terms in parentheses: -(5(x-6)), so:We get rid of parentheses
5(x-6)
We multiply parentheses
5x-30
Back to the equation:
-(5x-30)
8x^2-48x-5x+30=0
We add all the numbers together, and all the variables
8x^2-53x+30=0
a = 8; b = -53; c = +30;
Δ = b2-4ac
Δ = -532-4·8·30
Δ = 1849
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1849}=43$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-53)-43}{2*8}=\frac{10}{16} =5/8 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-53)+43}{2*8}=\frac{96}{16} =6 $
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