8x*42x-3=162x

Solution for 8x*42x-3=162x equation:

8x*42x-3=162x

We move all terms to the left:

8x*42x-3-(162x)=0

We add all the numbers together, and all the variables

-162x+8x*42x-3=0

Wy multiply elements

336x^2-162x-3=0

a = 336; b = -162; c = -3;
Δ = b2-4ac
Δ = -1622-4·336·(-3)
Δ = 30276
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{30276}=174$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-162)-174}{2*336}=\frac{-12}{672}
=-1/56
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-162)+174}{2*336}=\frac{336}{672}
=1/2
$