8x+((1-4x)/8)=7

Solution for 8x+((1-4x)/8)=7 equation:

8x+((1-4x)/8)=7

We move all terms to the left:

8x+((1-4x)/8)-(7)=0

We add all the numbers together, and all the variables

8x+((-4x+1)/8)-7=0

We multiply all the terms by the denominator


8x*8)+((-4x+1)-7*8)=0

We add all the numbers together, and all the variables

8x*8)+((-4x+1)=0

Wy multiply elements

64x^2=0

a = 64; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·64·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{128}=0$