8x+(3x-10)=2(7x-10)

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Solution for 8x+(3x-10)=2(7x-10) equation:



8x+(3x-10)=2(7x-10)
We move all terms to the left:
8x+(3x-10)-(2(7x-10))=0
We get rid of parentheses
8x+3x-(2(7x-10))-10=0
We calculate terms in parentheses: -(2(7x-10)), so:
2(7x-10)
We multiply parentheses
14x-20
Back to the equation:
-(14x-20)
We add all the numbers together, and all the variables
11x-(14x-20)-10=0
We get rid of parentheses
11x-14x+20-10=0
We add all the numbers together, and all the variables
-3x+10=0
We move all terms containing x to the left, all other terms to the right
-3x=-10
x=-10/-3
x=3+1/3

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