8x+(5x-6-4x+1)=x-(x-4

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Solution for 8x+(5x-6-4x+1)=x-(x-4 equation: 



8x+(5x-6-4x+1)=x-(x-4

We move all terms to the left:

8x+(5x-6-4x+1)-(x-(x-4)=0

We add all the numbers together, and all the variables

8x+(x-5)-(x-(x-4)=0

We get rid of parentheses

8x+x-(x-(x-4)-5=0

We add all the numbers together, and all the variables

9x-(x-(x-4)-5=0

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