8x+(5x-6-4x+1)=x-4)

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Solution for 8x+(5x-6-4x+1)=x-4) equation: 



8x+(5x-6-4x+1)=x-4)

We move all terms to the left:

8x+(5x-6-4x+1)-(x-4))=0

We add all the numbers together, and all the variables

8x+(x-5)-(x-4))=0

We get rid of parentheses

8x+x-x-5+4)=0

We add all the numbers together, and all the variables

8x=0

x=0/8

x=0

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