8x+(x-6-4x+1)=x-(x-4)

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Solution for 8x+(x-6-4x+1)=x-(x-4) equation: 



8x+(x-6-4x+1)=x-(x-4)

We move all terms to the left:

8x+(x-6-4x+1)-(x-(x-4))=0

We add all the numbers together, and all the variables

8x+(-3x-5)-(x-(x-4))=0

We get rid of parentheses

8x-3x-(x-(x-4))-5=0



We calculate terms in parentheses: -(x-(x-4)), so:

x-(x-4)

We get rid of parentheses

x-x+4

We add all the numbers together, and all the variables

4

Back to the equation:

-(4)



We add all the numbers together, and all the variables

5x-9=0

We move all terms containing x to the left, all other terms to the right

5x=9

x=9/5

x=1+4/5

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