8x+-2(x+1)=2(3x+-1)

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Solution for 8x+-2(x+1)=2(3x+-1) equation: 



8x+-2(x+1)=2(3x+-1)

We move all terms to the left:

8x+-2(x+1)-(2(3x+-1))=0

We add all the numbers together, and all the variables

8x-2(x+1)-(2(3x-1))+=0

We add all the numbers together, and all the variables

8x-2(x+1)-(2(3x-1))=0

We multiply parentheses

8x-2x-(2(3x-1))-2=0



We calculate terms in parentheses: -(2(3x-1)), so:

2(3x-1)

We multiply parentheses

6x-2

Back to the equation:

-(6x-2)



We add all the numbers together, and all the variables

6x-(6x-2)-2=0

We get rid of parentheses

6x-6x+2-2=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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