8x+-3(x+-4)=3(x+-4)-6

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Solution for 8x+-3(x+-4)=3(x+-4)-6 equation:



8x+-3(x+-4)=3(x+-4)-6
We move all terms to the left:
8x+-3(x+-4)-(3(x+-4)-6)=0
We add all the numbers together, and all the variables
8x-3(x-4)-(3(x-4)-6)+=0
We add all the numbers together, and all the variables
8x-3(x-4)-(3(x-4)-6)=0
We multiply parentheses
8x-3x-(3(x-4)-6)+12=0
We calculate terms in parentheses: -(3(x-4)-6), so:
3(x-4)-6
We multiply parentheses
3x-12-6
We add all the numbers together, and all the variables
3x-18
Back to the equation:
-(3x-18)
We add all the numbers together, and all the variables
5x-(3x-18)+12=0
We get rid of parentheses
5x-3x+18+12=0
We add all the numbers together, and all the variables
2x+30=0
We move all terms containing x to the left, all other terms to the right
2x=-30
x=-30/2
x=-15

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