8x+10=4(x-4)-2

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Solution for 8x+10=4(x-4)-2 equation: 



8x+10=4(x-4)-2

We move all terms to the left:

8x+10-(4(x-4)-2)=0



We calculate terms in parentheses: -(4(x-4)-2), so:

4(x-4)-2

We multiply parentheses

4x-16-2

We add all the numbers together, and all the variables

4x-18

Back to the equation:

-(4x-18)



We get rid of parentheses

8x-4x+18+10=0

We add all the numbers together, and all the variables

4x+28=0

We move all terms containing x to the left, all other terms to the right

4x=-28

x=-28/4

x=-7

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