8x+12+4x=4x+34-(2x+2)

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Solution for 8x+12+4x=4x+34-(2x+2) equation: 



8x+12+4x=4x+34-(2x+2)

We move all terms to the left:

8x+12+4x-(4x+34-(2x+2))=0

We add all the numbers together, and all the variables

12x-(4x+34-(2x+2))+12=0



We calculate terms in parentheses: -(4x+34-(2x+2)), so:

4x+34-(2x+2)

determiningTheFunctionDomain
4x-(2x+2)+34

We get rid of parentheses

4x-2x-2+34

We add all the numbers together, and all the variables

2x+32

Back to the equation:

-(2x+32)



We get rid of parentheses

12x-2x-32+12=0

We add all the numbers together, and all the variables

10x-20=0

We move all terms containing x to the left, all other terms to the right

10x=20

x=20/10

x=2

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