8x+12=(10x-4)+6

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Solution for 8x+12=(10x-4)+6 equation: 



8x+12=(10x-4)+6

We move all terms to the left:

8x+12-((10x-4)+6)=0



We calculate terms in parentheses: -((10x-4)+6), so:

(10x-4)+6

We get rid of parentheses

10x-4+6

We add all the numbers together, and all the variables

10x+2

Back to the equation:

-(10x+2)



We get rid of parentheses

8x-10x-2+12=0

We add all the numbers together, and all the variables

-2x+10=0

We move all terms containing x to the left, all other terms to the right

-2x=-10

x=-10/-2

x=+5

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