8x+12=(20x-7)-(10x-9)

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Solution for 8x+12=(20x-7)-(10x-9) equation: 



8x+12=(20x-7)-(10x-9)

We move all terms to the left:

8x+12-((20x-7)-(10x-9))=0



We calculate terms in parentheses: -((20x-7)-(10x-9)), so:

(20x-7)-(10x-9)

We get rid of parentheses

20x-10x-7+9

We add all the numbers together, and all the variables

10x+2

Back to the equation:

-(10x+2)



We get rid of parentheses

8x-10x-2+12=0

We add all the numbers together, and all the variables

-2x+10=0

We move all terms containing x to the left, all other terms to the right

-2x=-10

x=-10/-2

x=+5

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