8x+15=(2/3x)-3

Solution for 8x+15=(2/3x)-3 equation:

8x+15=(2/3x)-3

We move all terms to the left:

8x+15-((2/3x)-3)=0


Domain of the equation: 3x)-3)!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

8x-((+2/3x)-3)+15=0

We multiply all the terms by the denominator


8x*3x)-3)-((+15*3x)-3)+2=0

Wy multiply elements

24x^2+45x=0

a = 24; b = 45; c = 0;
Δ = b2-4ac
Δ = 452-4·24·0
Δ = 2025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2025}=45$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(45)-45}{2*24}=\frac{-90}{48}
=-1+7/8
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(45)+45}{2*24}=\frac{0}{48}
=0
$