8x+1=(3x+1)/5

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Solution for 8x+1=(3x+1)/5 equation: 



8x+1=(3x+1)/5

We move all terms to the left:

8x+1-((3x+1)/5)=0

We multiply all the terms by the denominator


8x*5)-((3x+1)+1*5)=0

We add all the numbers together, and all the variables

8x*5)-((3x+1)=0

Wy multiply elements

40x^2=0

a = 40; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·40·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{80}=0$

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