8x+2(3x+1)=8x+2(1x+1)

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Solution for 8x+2(3x+1)=8x+2(1x+1) equation: 



8x+2(3x+1)=8x+2(1x+1)

We move all terms to the left:

8x+2(3x+1)-(8x+2(1x+1))=0

We add all the numbers together, and all the variables

8x+2(3x+1)-(8x+2(x+1))=0

We multiply parentheses

8x+6x-(8x+2(x+1))+2=0



We calculate terms in parentheses: -(8x+2(x+1)), so:

8x+2(x+1)

We multiply parentheses

8x+2x+2

We add all the numbers together, and all the variables

10x+2

Back to the equation:

-(10x+2)



We add all the numbers together, and all the variables

14x-(10x+2)+2=0

We get rid of parentheses

14x-10x-2+2=0

We add all the numbers together, and all the variables

4x=0

x=0/4

x=0

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