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8x+2(5-x)=3(2x+3)+1
We move all terms to the left:
8x+2(5-x)-(3(2x+3)+1)=0
We add all the numbers together, and all the variables
8x+2(-1x+5)-(3(2x+3)+1)=0
We multiply parentheses
8x-2x-(3(2x+3)+1)+10=0
We calculate terms in parentheses: -(3(2x+3)+1), so:We add all the numbers together, and all the variables
3(2x+3)+1
We multiply parentheses
6x+9+1
We add all the numbers together, and all the variables
6x+10
Back to the equation:
-(6x+10)
6x-(6x+10)+10=0
We get rid of parentheses
6x-6x-10+10=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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