8x+2(x-3)=5+3(2x-1)

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Solution for 8x+2(x-3)=5+3(2x-1) equation: 



8x+2(x-3)=5+3(2x-1)

We move all terms to the left:

8x+2(x-3)-(5+3(2x-1))=0

We multiply parentheses

8x+2x-(5+3(2x-1))-6=0



We calculate terms in parentheses: -(5+3(2x-1)), so:

5+3(2x-1)

determiningTheFunctionDomain
3(2x-1)+5

We multiply parentheses

6x-3+5

We add all the numbers together, and all the variables

6x+2

Back to the equation:

-(6x+2)



We add all the numbers together, and all the variables

10x-(6x+2)-6=0

We get rid of parentheses

10x-6x-2-6=0

We add all the numbers together, and all the variables

4x-8=0

We move all terms containing x to the left, all other terms to the right

4x=8

x=8/4

x=2

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