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8x+2=2(2x+3/2)
We move all terms to the left:
8x+2-(2(2x+3/2))=0
We add all the numbers together, and all the variables
8x-(2(+2x+3/2))+2=0
We multiply all the terms by the denominator
8x*2))-(2(+2x+3+2*2))=0
We add all the numbers together, and all the variables
8x*2))-(2(2x+7))=0
We add all the numbers together, and all the variables
8x*2))-(2(2x=0
Wy multiply elements
16x^2=0
a = 16; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·16·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$x=\frac{-b}{2a}=\frac{0}{32}=0$
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