8x+3(1/3x-6)=1x+12

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Solution for 8x+3(1/3x-6)=1x+12 equation: 



8x+3(1/3x-6)=1x+12

We move all terms to the left:

8x+3(1/3x-6)-(1x+12)=0



Domain of the equation: 3x-6)!=0

x∈R



We add all the numbers together, and all the variables

8x+3(1/3x-6)-(x+12)=0

We multiply parentheses

8x+3x-(x+12)-18=0

We get rid of parentheses

8x+3x-x-12-18=0

We add all the numbers together, and all the variables

10x-30=0

We move all terms containing x to the left, all other terms to the right

10x=30

x=30/10

x=3

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