8x+3(2x-4)=3(x-6)

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Solution for 8x+3(2x-4)=3(x-6) equation: 



8x+3(2x-4)=3(x-6)

We move all terms to the left:

8x+3(2x-4)-(3(x-6))=0

We multiply parentheses

8x+6x-(3(x-6))-12=0



We calculate terms in parentheses: -(3(x-6)), so:

3(x-6)

We multiply parentheses

3x-18

Back to the equation:

-(3x-18)



We add all the numbers together, and all the variables

14x-(3x-18)-12=0

We get rid of parentheses

14x-3x+18-12=0

We add all the numbers together, and all the variables

11x+6=0

We move all terms containing x to the left, all other terms to the right

11x=-6

x=-6/11

x=-6/11

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