8x+3(x+5)-5(4-x)=2

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Solution for 8x+3(x+5)-5(4-x)=2 equation: 



8x+3(x+5)-5(4-x)=2

We move all terms to the left:

8x+3(x+5)-5(4-x)-(2)=0

We add all the numbers together, and all the variables

8x+3(x+5)-5(-1x+4)-2=0

We multiply parentheses

8x+3x+5x+15-20-2=0

We add all the numbers together, and all the variables

16x-7=0

We move all terms containing x to the left, all other terms to the right

16x=7

x=7/16

x=7/16

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