8x+3(x-4)=-3x+6+8x

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Solution for 8x+3(x-4)=-3x+6+8x equation: 



8x+3(x-4)=-3x+6+8x

We move all terms to the left:

8x+3(x-4)-(-3x+6+8x)=0

We add all the numbers together, and all the variables

8x+3(x-4)-(5x+6)=0

We multiply parentheses

8x+3x-(5x+6)-12=0

We get rid of parentheses

8x+3x-5x-6-12=0

We add all the numbers together, and all the variables

6x-18=0

We move all terms containing x to the left, all other terms to the right

6x=18

x=18/6

x=3

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