8x+3-10x=-2(x-2)+38x+3-10x=-2(x-2)+3

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Solution for 8x+3-10x=-2(x-2)+38x+3-10x=-2(x-2)+3 equation: 



8x+3-10x=-2(x-2)+38x+3-10x=-2(x-2)+3

We move all terms to the left:

8x+3-10x-(-2(x-2)+38x+3-10x)=0

We add all the numbers together, and all the variables

-2x-(-2(x-2)+38x+3-10x)+3=0



We calculate terms in parentheses: -(-2(x-2)+38x+3-10x), so:

-2(x-2)+38x+3-10x

determiningTheFunctionDomain
-2(x-2)+38x-10x+3

We add all the numbers together, and all the variables

28x-2(x-2)+3

We multiply parentheses

28x-2x+4+3

We add all the numbers together, and all the variables

26x+7

Back to the equation:

-(26x+7)



We get rid of parentheses

-2x-26x-7+3=0

We add all the numbers together, and all the variables

-28x-4=0

We move all terms containing x to the left, all other terms to the right

-28x=4

x=4/-28

x=-1/7

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