8x+3-10x=-29(x-2)+3

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Solution for 8x+3-10x=-29(x-2)+3 equation:



8x+3-10x=-29(x-2)+3
We move all terms to the left:
8x+3-10x-(-29(x-2)+3)=0
We add all the numbers together, and all the variables
-2x-(-29(x-2)+3)+3=0
We calculate terms in parentheses: -(-29(x-2)+3), so:
-29(x-2)+3
We multiply parentheses
-29x+58+3
We add all the numbers together, and all the variables
-29x+61
Back to the equation:
-(-29x+61)
We get rid of parentheses
-2x+29x-61+3=0
We add all the numbers together, and all the variables
27x-58=0
We move all terms containing x to the left, all other terms to the right
27x=58
x=58/27
x=2+4/27

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