8x+3-3(-3x-2)=3(x-1)

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Solution for 8x+3-3(-3x-2)=3(x-1) equation: 



8x+3-3(-3x-2)=3(x-1)

We move all terms to the left:

8x+3-3(-3x-2)-(3(x-1))=0

We multiply parentheses

8x+9x-(3(x-1))+6+3=0



We calculate terms in parentheses: -(3(x-1)), so:

3(x-1)

We multiply parentheses

3x-3

Back to the equation:

-(3x-3)



We add all the numbers together, and all the variables

17x-(3x-3)+9=0

We get rid of parentheses

17x-3x+3+9=0

We add all the numbers together, and all the variables

14x+12=0

We move all terms containing x to the left, all other terms to the right

14x=-12

x=-12/14

x=-6/7

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