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8x+3/4(8x+4)=3(3x+6)-7
We move all terms to the left:
8x+3/4(8x+4)-(3(3x+6)-7)=0
Domain of the equation: 4(8x+4)!=0We multiply all the terms by the denominator
x∈R
8x*4(8x+4)-((3(3x+6)-7))*4(8x+4)+3=0
We calculate terms in parentheses: -((3(3x+6)-7))*4(8x+4), so:Wy multiply elements
(3(3x+6)-7))*4(8x+4
32x^2(8-((3(3x+6)-7))*4(8x+4)+3=0
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