8x+32=1/5(25x-15)-4x

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Solution for 8x+32=1/5(25x-15)-4x equation: 



8x+32=1/5(25x-15)-4x

We move all terms to the left:

8x+32-(1/5(25x-15)-4x)=0



Domain of the equation: 5(25x-15)-4x)!=0

x∈R



We multiply all the terms by the denominator


8x*5(25x-15)-4x)-(1+32*5(25x-15)-4x)=0

Wy multiply elements

40x^2(2-4x)-(1+160x(2-4x)=0



We calculate terms in parentheses: -(1+160x(2-4x), so:

1+160x(2-4x

determiningTheFunctionDomain
160x(2-4x+1

Back to the equation:

-(160x(2-4x+1)



We add all the numbers together, and all the variables

40x^2(-4x+2)-(160x(-4x+3)=0



We calculate terms in parentheses: -(160x(-4x+3), so:

160x(-4x+3





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160x(-4x+3





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160x(-4x+3





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160x(-4x+3





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160x(-4x+3





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