8x+38=-2(-19-4x)x=

Solution for 8x+38=-2(-19-4x)x= equation:

8x+38=-2(-19-4x)x=

We move all terms to the left:

8x+38-(-2(-19-4x)x)=0

We add all the numbers together, and all the variables

8x-(-2(-4x-19)x)+38=0


We calculate terms in parentheses: -(-2(-4x-19)x), so:

-2(-4x-19)x

We multiply parentheses

8x^2+38x

Back to the equation:

-(8x^2+38x)


We get rid of parentheses

-8x^2+8x-38x+38=0

We add all the numbers together, and all the variables

-8x^2-30x+38=0

a = -8; b = -30; c = +38;
Δ = b2-4ac
Δ = -302-4·(-8)·38
Δ = 2116
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2116}=46$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-30)-46}{2*-8}=\frac{-16}{-16}
=1
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-30)+46}{2*-8}=\frac{76}{-16}
=-4+3/4
$