8x+38=-3(-6+4x)

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Solution for 8x+38=-3(-6+4x) equation: 



8x+38=-3(-6+4x)

We move all terms to the left:

8x+38-(-3(-6+4x))=0

We add all the numbers together, and all the variables

8x-(-3(4x-6))+38=0



We calculate terms in parentheses: -(-3(4x-6)), so:

-3(4x-6)

We multiply parentheses

-12x+18

Back to the equation:

-(-12x+18)



We get rid of parentheses

8x+12x-18+38=0

We add all the numbers together, and all the variables

20x+20=0

We move all terms containing x to the left, all other terms to the right

20x=-20

x=-20/20

x=-1

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