8x+38=-7(-3-2x)-1

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Solution for 8x+38=-7(-3-2x)-1 equation: 



8x+38=-7(-3-2x)-1

We move all terms to the left:

8x+38-(-7(-3-2x)-1)=0

We add all the numbers together, and all the variables

8x-(-7(-2x-3)-1)+38=0



We calculate terms in parentheses: -(-7(-2x-3)-1), so:

-7(-2x-3)-1

We multiply parentheses

14x+21-1

We add all the numbers together, and all the variables

14x+20

Back to the equation:

-(14x+20)



We get rid of parentheses

8x-14x-20+38=0

We add all the numbers together, and all the variables

-6x+18=0

We move all terms containing x to the left, all other terms to the right

-6x=-18

x=-18/-6

x=+3

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