8x+38=-7(-3-2x)-1

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Solution for 8x+38=-7(-3-2x)-1 equation:



8x+38=-7(-3-2x)-1
We move all terms to the left:
8x+38-(-7(-3-2x)-1)=0
We add all the numbers together, and all the variables
8x-(-7(-2x-3)-1)+38=0
We calculate terms in parentheses: -(-7(-2x-3)-1), so:
-7(-2x-3)-1
We multiply parentheses
14x+21-1
We add all the numbers together, and all the variables
14x+20
Back to the equation:
-(14x+20)
We get rid of parentheses
8x-14x-20+38=0
We add all the numbers together, and all the variables
-6x+18=0
We move all terms containing x to the left, all other terms to the right
-6x=-18
x=-18/-6
x=+3

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