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8x+3=8(x+1)-x
We move all terms to the left:
8x+3-(8(x+1)-x)=0
We calculate terms in parentheses: -(8(x+1)-x), so:We get rid of parentheses
8(x+1)-x
We add all the numbers together, and all the variables
-1x+8(x+1)
We multiply parentheses
-1x+8x+8
We add all the numbers together, and all the variables
7x+8
Back to the equation:
-(7x+8)
8x-7x-8+3=0
We add all the numbers together, and all the variables
x-5=0
We move all terms containing x to the left, all other terms to the right
x=5
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