8x+4(3x-3)=(6x+4)-4

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Solution for 8x+4(3x-3)=(6x+4)-4 equation: 



8x+4(3x-3)=(6x+4)-4

We move all terms to the left:

8x+4(3x-3)-((6x+4)-4)=0

We multiply parentheses

8x+12x-((6x+4)-4)-12=0



We calculate terms in parentheses: -((6x+4)-4), so:

(6x+4)-4

We get rid of parentheses

6x+4-4

We add all the numbers together, and all the variables

6x

Back to the equation:

-(6x)



We add all the numbers together, and all the variables

14x-12=0

We move all terms containing x to the left, all other terms to the right

14x=12

x=12/14

x=6/7

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