8x+4(4+x)=3(x-6)+10x

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Solution for 8x+4(4+x)=3(x-6)+10x equation: 



8x+4(4+x)=3(x-6)+10x

We move all terms to the left:

8x+4(4+x)-(3(x-6)+10x)=0

We add all the numbers together, and all the variables

8x+4(x+4)-(3(x-6)+10x)=0

We multiply parentheses

8x+4x-(3(x-6)+10x)+16=0



We calculate terms in parentheses: -(3(x-6)+10x), so:

3(x-6)+10x

We add all the numbers together, and all the variables

10x+3(x-6)

We multiply parentheses

10x+3x-18

We add all the numbers together, and all the variables

13x-18

Back to the equation:

-(13x-18)



We add all the numbers together, and all the variables

12x-(13x-18)+16=0

We get rid of parentheses

12x-13x+18+16=0

We add all the numbers together, and all the variables

-1x+34=0

We move all terms containing x to the left, all other terms to the right

-x=-34

x=-34/-1

x=+34

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