8x+4(4x-3)=-(6x+4)-4

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Solution for 8x+4(4x-3)=-(6x+4)-4 equation: 



8x+4(4x-3)=-(6x+4)-4

We move all terms to the left:

8x+4(4x-3)-(-(6x+4)-4)=0

We multiply parentheses

8x+16x-(-(6x+4)-4)-12=0



We calculate terms in parentheses: -(-(6x+4)-4), so:

-(6x+4)-4

We get rid of parentheses

-6x-4-4

We add all the numbers together, and all the variables

-6x-8

Back to the equation:

-(-6x-8)



We add all the numbers together, and all the variables

24x-(-6x-8)-12=0

We get rid of parentheses

24x+6x+8-12=0

We add all the numbers together, and all the variables

30x-4=0

We move all terms containing x to the left, all other terms to the right

30x=4

x=4/30

x=2/15

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