8x+4(4x-3)=4(3x+3)-48

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Solution for 8x+4(4x-3)=4(3x+3)-48 equation: 



8x+4(4x-3)=4(3x+3)-48

We move all terms to the left:

8x+4(4x-3)-(4(3x+3)-48)=0

We multiply parentheses

8x+16x-(4(3x+3)-48)-12=0



We calculate terms in parentheses: -(4(3x+3)-48), so:

4(3x+3)-48

We multiply parentheses

12x+12-48

We add all the numbers together, and all the variables

12x-36

Back to the equation:

-(12x-36)



We add all the numbers together, and all the variables

24x-(12x-36)-12=0

We get rid of parentheses

24x-12x+36-12=0

We add all the numbers together, and all the variables

12x+24=0

We move all terms containing x to the left, all other terms to the right

12x=-24

x=-24/12

x=-2

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