8x+4(4x-3)=4(4x-3)=4(6x+4)-4

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Solution for 8x+4(4x-3)=4(4x-3)=4(6x+4)-4 equation: 



8x+4(4x-3)=4(4x-3)=4(6x+4)-4

We move all terms to the left:

8x+4(4x-3)-(4(4x-3))=0

We multiply parentheses

8x+16x-(4(4x-3))-12=0



We calculate terms in parentheses: -(4(4x-3)), so:

4(4x-3)

We multiply parentheses

16x-12

Back to the equation:

-(16x-12)



We add all the numbers together, and all the variables

24x-(16x-12)-12=0

We get rid of parentheses

24x-16x+12-12=0

We add all the numbers together, and all the variables

8x=0

x=0/8

x=0

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