8x+4(4x-3)=4(5x+4)-4

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Solution for 8x+4(4x-3)=4(5x+4)-4 equation: 



8x+4(4x-3)=4(5x+4)-4

We move all terms to the left:

8x+4(4x-3)-(4(5x+4)-4)=0

We multiply parentheses

8x+16x-(4(5x+4)-4)-12=0



We calculate terms in parentheses: -(4(5x+4)-4), so:

4(5x+4)-4

We multiply parentheses

20x+16-4

We add all the numbers together, and all the variables

20x+12

Back to the equation:

-(20x+12)



We add all the numbers together, and all the variables

24x-(20x+12)-12=0

We get rid of parentheses

24x-20x-12-12=0

We add all the numbers together, and all the variables

4x-24=0

We move all terms containing x to the left, all other terms to the right

4x=24

x=24/4

x=6

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