8x+4(4x-3)=4(6x+4)-4x

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Solution for 8x+4(4x-3)=4(6x+4)-4x equation: 



8x+4(4x-3)=4(6x+4)-4x

We move all terms to the left:

8x+4(4x-3)-(4(6x+4)-4x)=0

We multiply parentheses

8x+16x-(4(6x+4)-4x)-12=0



We calculate terms in parentheses: -(4(6x+4)-4x), so:

4(6x+4)-4x

We add all the numbers together, and all the variables

-4x+4(6x+4)

We multiply parentheses

-4x+24x+16

We add all the numbers together, and all the variables

20x+16

Back to the equation:

-(20x+16)



We add all the numbers together, and all the variables

24x-(20x+16)-12=0

We get rid of parentheses

24x-20x-16-12=0

We add all the numbers together, and all the variables

4x-28=0

We move all terms containing x to the left, all other terms to the right

4x=28

x=28/4

x=7

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