8x+4(4x-3x)=4(6x+4)-4x

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Solution for 8x+4(4x-3x)=4(6x+4)-4x equation: 



8x+4(4x-3x)=4(6x+4)-4x

We move all terms to the left:

8x+4(4x-3x)-(4(6x+4)-4x)=0

We add all the numbers together, and all the variables

8x+4(+x)-(4(6x+4)-4x)=0

We multiply parentheses

8x+4x-(4(6x+4)-4x)=0



We calculate terms in parentheses: -(4(6x+4)-4x), so:

4(6x+4)-4x

We add all the numbers together, and all the variables

-4x+4(6x+4)

We multiply parentheses

-4x+24x+16

We add all the numbers together, and all the variables

20x+16

Back to the equation:

-(20x+16)



We add all the numbers together, and all the variables

12x-(20x+16)=0

We get rid of parentheses

12x-20x-16=0

We add all the numbers together, and all the variables

-8x-16=0

We move all terms containing x to the left, all other terms to the right

-8x=16

x=16/-8

x=-2

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