8x+4(8x-3)=4(6x+4)-4

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Solution for 8x+4(8x-3)=4(6x+4)-4 equation:



8x+4(8x-3)=4(6x+4)-4
We move all terms to the left:
8x+4(8x-3)-(4(6x+4)-4)=0
We multiply parentheses
8x+32x-(4(6x+4)-4)-12=0
We calculate terms in parentheses: -(4(6x+4)-4), so:
4(6x+4)-4
We multiply parentheses
24x+16-4
We add all the numbers together, and all the variables
24x+12
Back to the equation:
-(24x+12)
We add all the numbers together, and all the variables
40x-(24x+12)-12=0
We get rid of parentheses
40x-24x-12-12=0
We add all the numbers together, and all the variables
16x-24=0
We move all terms containing x to the left, all other terms to the right
16x=24
x=24/16
x=1+1/2

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