8x+4(x+2)=7(2x-1)

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Solution for 8x+4(x+2)=7(2x-1) equation: 



8x+4(x+2)=7(2x-1)

We move all terms to the left:

8x+4(x+2)-(7(2x-1))=0

We multiply parentheses

8x+4x-(7(2x-1))+8=0



We calculate terms in parentheses: -(7(2x-1)), so:

7(2x-1)

We multiply parentheses

14x-7

Back to the equation:

-(14x-7)



We add all the numbers together, and all the variables

12x-(14x-7)+8=0

We get rid of parentheses

12x-14x+7+8=0

We add all the numbers together, and all the variables

-2x+15=0

We move all terms containing x to the left, all other terms to the right

-2x=-15

x=-15/-2

x=7+1/2

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