8x+4-2(-3x-4)=2(x-2)

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Solution for 8x+4-2(-3x-4)=2(x-2) equation: 



8x+4-2(-3x-4)=2(x-2)

We move all terms to the left:

8x+4-2(-3x-4)-(2(x-2))=0

We multiply parentheses

8x+6x-(2(x-2))+8+4=0



We calculate terms in parentheses: -(2(x-2)), so:

2(x-2)

We multiply parentheses

2x-4

Back to the equation:

-(2x-4)



We add all the numbers together, and all the variables

14x-(2x-4)+12=0

We get rid of parentheses

14x-2x+4+12=0

We add all the numbers together, and all the variables

12x+16=0

We move all terms containing x to the left, all other terms to the right

12x=-16

x=-16/12

x=-1+1/3

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