8x+4-2(-5x-5)=4(x-1)

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Solution for 8x+4-2(-5x-5)=4(x-1) equation: 



8x+4-2(-5x-5)=4(x-1)

We move all terms to the left:

8x+4-2(-5x-5)-(4(x-1))=0

We multiply parentheses

8x+10x-(4(x-1))+10+4=0



We calculate terms in parentheses: -(4(x-1)), so:

4(x-1)

We multiply parentheses

4x-4

Back to the equation:

-(4x-4)



We add all the numbers together, and all the variables

18x-(4x-4)+14=0

We get rid of parentheses

18x-4x+4+14=0

We add all the numbers together, and all the variables

14x+18=0

We move all terms containing x to the left, all other terms to the right

14x=-18

x=-18/14

x=-1+2/7

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