8x+4-4(-3x-1)=2(x-3)

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Solution for 8x+4-4(-3x-1)=2(x-3) equation: 



8x+4-4(-3x-1)=2(x-3)

We move all terms to the left:

8x+4-4(-3x-1)-(2(x-3))=0

We multiply parentheses

8x+12x-(2(x-3))+4+4=0



We calculate terms in parentheses: -(2(x-3)), so:

2(x-3)

We multiply parentheses

2x-6

Back to the equation:

-(2x-6)



We add all the numbers together, and all the variables

20x-(2x-6)+8=0

We get rid of parentheses

20x-2x+6+8=0

We add all the numbers together, and all the variables

18x+14=0

We move all terms containing x to the left, all other terms to the right

18x=-14

x=-14/18

x=-7/9

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