8x+40=-8(1+7x)

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Solution for 8x+40=-8(1+7x) equation: 



8x+40=-8(1+7x)

We move all terms to the left:

8x+40-(-8(1+7x))=0

We add all the numbers together, and all the variables

8x-(-8(7x+1))+40=0



We calculate terms in parentheses: -(-8(7x+1)), so:

-8(7x+1)

We multiply parentheses

-56x-8

Back to the equation:

-(-56x-8)



We get rid of parentheses

8x+56x+8+40=0

We add all the numbers together, and all the variables

64x+48=0

We move all terms containing x to the left, all other terms to the right

64x=-48

x=-48/64

x=-3/4

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