8x+40=6x=12

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Solution for 8x+40=6x=12 equation: 



8x+40=6x=12

We move all terms to the left:

8x+40-(6x)=0

We add all the numbers together, and all the variables

2x+40=0

We move all terms containing x to the left, all other terms to the right

2x=-40

x=-40/2

x=-20

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