8x+40y=11;x=1-5y

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2x+y=8
x+3y=14

Solution for 8x+40y=11;x=1-5y system of equations: 


  • /| 8*x+40*y-11 = 0| x+5*y-1 = 0
  • We try to solve the equation: 8*x+40*y-11 = 0
  • 8*x+40*y-11 = 0 // - 8*x-11
  • 40*y = -(8*x-11) // : 40
  • y = (-(8*x-11))/40
  • y = (11-(8*x))/40
  • We insert the solution into one of the initial equations of our system of equations
  • We get a system of equations:
  • /| 5*((11-(8*x))/40)+x-1 = 0| y = (11-(8*x))/40
  • (5*(11-8*x))/40+x-1 = 0
  • 11/8-1 = 0
  • 3/8 = 0
  • 3/8 = 0
  • x belongs to the empty set
  • The system of equations does not have any solution

 

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